[单选题]

2. Papermaking is_________ of ancient China.

A. one of greatest inventor

B. one of the greatest inventors

C. one of greatest invention

D. one of the greatest inventions

参考答案与解析:

相关试题

CH3CH2-|||-=c =c-|||-3-|||-H-|||-2. Br CH=CH2-|||-CH(CH3)2

CH3CH2-|||-=c =c-|||-3-|||-H-|||-2. Br CH=CH2-|||-CH(CH3)2

  • 查看答案
  • (4)(5)(6)2.(1)(2) 1.用系统命名法命名下列化合物:-|||-CH2CH3-|||-(1)CH3CHCHCH2CHCH3-|||-CH3 CH3-|||-(2)(C2H5)2CHCH(

    (4)(5)(6)2.(1)(2) 1.用系统命名法命名下列化合物:-|||-CH2CH3-|||-(1)CH3CHCHCH2CHCH3-|||-CH3 CH3

  • 查看答案
  • 2.写出下列构造式的系统命名。-|||-OH-|||-(1)CH3CH2 CHCHCH3-|||-CH3-|||-H3C H-|||-(2) C=C-|||-H CH2CHOHCH3-|||-(3)C

    2.写出下列构造式的系统命名。-|||-OH-|||-(1)CH3CH2 CHCHCH3-|||-CH3-|||-H3C H-|||-(2) C=C-|||-H

  • 查看答案
  • 下列化合物沸点从小到大次序是()。(a)CH3CH2CH2COOH;(b)CH3CH2CH2CH3;(c)CH3CH2CH2CH2OH;(d)CH3CH2CH2CHO

    下列化合物沸点从小到大次序是()。(a)CH3CH2CH2COOH;(b)CH3CH2CH2CH3;(c)CH3CH2CH2CH2OH;(d)CH3CH2CH2

  • 查看答案
  • 熵弹性-|||-7.应力松弛-|||-二、判断题-|||-1.柔顺性-|||-CH2 CH2 O-|||-A) CH2 CH2 B) -|||-1.高分子链的远程结构-|||-2.高斯链-|||-3.

    熵弹性-|||-7.应力松弛-|||-二、判断题-|||-1.柔顺性-|||-CH2 CH2 O-|||-A) CH2 CH2 B) -|||-1.高分子链的远

  • 查看答案
  • 用下列哪个试剂可将CH3CH=CHCH2CH2CHO还原为 CH3CH2CH2CH2CH2 CH2OH

    用下列哪个试剂可将CH3CH=CHCH2CH2CHO还原为 CH3CH2CH2CH2CH2 CH2OHA. NaBH4B. LiHAl4C. H2+PdD. N

  • 查看答案
  • 下列化合物或基团不存在共轭体系的是:A.CH2=CH-CH2-CH=CH2B.CH2=CH-CH+-CH=CH2C.H2=CCH3-CH=CH2D.CH2=CH-CH=CHCH2+

    下列化合物或基团不存在共轭体系的是:A.CH2=CH-CH2-CH=CH2B.CH2=CH-CH+-CH=CH2C.H2=CCH3-CH=CH2D.CH2=CH

  • 查看答案
  • CH3(CH2)2CH2+(Ⅰ);CH3CH+CH2CH3(Ⅱ);(CH3)3C

    [单选题]CH3(CH2)2CH2+(Ⅰ);CH3CH+CH2CH3(Ⅱ);(CH3)3C+(Ⅲ)三种碳正离子的稳定性顺序如何?()A . (Ⅰ)>(Ⅱ)>(Ⅲ);B . (Ⅰ)<(Ⅱ)<(Ⅲ);C . (Ⅱ)>(Ⅰ)>(Ⅲ);D . (Ⅱ)>(Ⅲ)>(Ⅰ)。

  • 查看答案
  • 【简答题】列出下列单体所组成的高聚物熔点顺序,并说明理由. CH3—CH=CH2; CH3—CH2—CH=CH2; CH2=CH2 CH3CH2CH2CH=CH2; CH

    【简答题】列出下列单体所组成的高聚物熔点顺序,并说明理由. CH3—CH=CH2; CH3—CH2—CH=CH2; CH2=CH2 CH

  • 查看答案
  • CH3-|||-CH3CHCHCHCH2CH3-|||-CH3 CH2CH3 2.CH3-|||-CH3CHCHCHCH2CH3-|||-CH3 CH2CH3 3. CH3-|||-CH3CH

    CH3-|||-CH3CHCHCHCH2CH3-|||-CH3 CH2CH3 2.CH3-|||-CH3CHCHCHCH2CH3-|||-CH3 CH2CH

  • 查看答案