int i,n; printf("\nplease enter an integer number between2 and 5000:"); scanf("%d",&n); printf("\n\nThe prime factor(s)of%d is(are):",n): for(i=2;i<n;i4+) if((!(n%i))&&(Prime(i))) printf("%4d,",i); printf("\n"); }
[单选题]阅读FORTRAN程序:READ(*,*)ND0 10 K=1,NS=S+K**210 CONTINUEWRLTE(*,100)S100 FORM
[单选题]阅读FORTRAN程序:READ(*,*)ND010K=1,NS=S+K**210 CONTINUEWRLTE(*,100)S100 FORMAT(
[单选题]阅读FORTRAN程序:READ(*,*)ND0 10 K=1,NS=S+K**210 CONTINUEWRLTE(*,100)S100 FORM
[单选题]阅读FORTRAN程序:READ(*,*)ND0 10 K=1,NS=S+K**210 CONTINUEWRLTE(*,100)S100 FORM
[单选题]阅读FORTRAN程序:READ(*,*)ND0 10 K=1,NS=S+K**210 CONTINUEWRLTE(*,100)S100 FORM
[单选题]阅读FORTRAN程序:READ(*,*)ND0 10 K=1,NS=S+K**210 CONTINUEWRLTE(*,100)S100 FORM
[单选题]阅读FORTRAN程序:READ(*,*)ND010K=1,NS=S+K**210 CONTINUEWRLTE(*,100)S100 FORMAT(
[单选题]有程序: long fib(int n) { if(n<2)return(fib(n-1)+fib(n-2)); else return(2); } main( ) {printf("%d/n",fib(3));} 该程序的输出结果是( )A.2B.4C.6D.8
[主观题]F.(n)=1 n>8 n<12F.(n)=2 n<2F.(n)=3 n=6F.(n)=4 n=other使用+ - * /和 sign(n)函数组合出 F(n)函数sign(n)=0 n=0sign(n)=-1 n<0sign(n)=1 n>0
[主观题]F.(n)=1 n>8 n<12F.(n)=2 n<2F.(n)=3 n=6F.(n)=4 n=other使用+ - * /和 sign(n)函数组合出 F(n)函数sign(n)=0 n=0sign(n)=-1 n<0sign(n)=1 n>0