以下程序的输出结果是

#include <stdio.h>

void prt (int *x, int*y, int*z)

{printf("%d,%d,%d/n",++*x,++*y,*(z++));}

main()

{int a=10,b=40,c=20;

prt (&a,&b,&c);prt (&a,&b,&c);}

A．11,42, 31 12,22,41

B．11,41,20 12,42,20

C．11,21,40 11,21,21

D．11,41,21 12,42,22

[单选题]以下程序的输出结果是（ ）。#include<stdio.h>void main(){int a,b,d=241; a=d/100%9; b=(-1)&&(-1); printf("%d,%d/n",a,b);}A．6,1 B．2,1 C．6,0 D．2,0

[单选题]下述程序的输出结果是#include<stdio.h>void main(){ int a[5]={2,4,6,8,10};int *p=a,**q=&p;printf("%d,",*(p++));printf("%d",**q); }A．4,4B．2,2C．4,5D．2,4

[单选题]下述程序的输出结果是#include<stdio.h>void main(){ int a[5]={2,4,6,8,10};int *p=a,**q=&p;printf("%d,",*(p++));printf("%d",**q); }A．4,4B．2,2C．4,5D．2,4

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[主观题]以下程序的输出结果是#include <stdio.h>main(){ int k=4,s=0; do{ if((k%3)==0) continue; s+=k;k++; }while(k>10); printf("s=%d/n",s);}