int MathMine(int x)
{
int m=0;
int i;
for(i=x-1; i<=x+1; i++)
{
if (i<0) continue;
if (i>31) break;
if (sta[i]=-1) m++;
}
return m;
}
A.3
B.4
C.5
D.6
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[单选题] 针对以下C语言程序段,假设sta[10]= -1,对于 x 的取值,需要(56)个测试用例能够满足分支覆盖的要求。int MathMine( int x ){int m = 0;int i;for( i = x-1; i <= x + 1; i++ ){if ( i < 0 ) continue;if ( i >31 ) break;if ( sta[i] == -1 ) m++;}return m;}(56)A.3B.4C.5D.6
[单选题] 针对以下 C 语言程序段,对于(MaxNum,Type)的取值,至少需要(62)个测试用例能够满足判定覆盖的要求。while ( MaxNum-- > 0 ){if ( 10 == Type )x = y * 2;elseif ( 100 == Type )x = y + 10;elsex = y - 20;}(62)A.5 B. 4 C. 3 D. 2
[单选题]针对以下C语言程序段,对于(MaxNum,Type)的取值,至少需要(62)个测试用例能够满足判定覆盖的要求。while(MaxNum-->0){ if(10==Type) x=y* 2; else if(100==Type) x=y +10; else x=y-20;}A.5B.4C.3D.2
[单选题]针对下面的程序段,对于(MaxNum,Type)的取值,至少需要______个测试用例才能够满足判定覆盖的要求。Whjle(MaxNum-->0){If(10==Type)x=y * 2;E.lse if(100==Type)x=y+20;}A.) 5B.) 4C.) 3D.) 2A.B.C.D.
[单选题]针对以下程序段,对于变量c的取值,至少需要(61)个测试用例才能够满足语句覆盖的要求。c=((u8_t*)q->payload)[i];switch(c){case SLIP_END: sio_send(SLIP_ESC,netif->state); sio_send(SLIP_ESC_END,netif->state); break;case SLIP_ESC: sio_send(SLIP_ESC,netif->state); sio_send(SLIP_ESC_ESC,netif->stat
[单选题] 针对下列程序段,对于(A,B,C)的取值,以下(56)测试用例组合能够满足语句覆盖的要求。IF ( ( A + 10 ) = 2 OR ( B -20 ) < 3 ) THEN C = 0 IF ( ( A+30 ) > 10 AND ( C - 30 ) < 0 ) THEN B = 30(56)A.(2,30,1)B.(-20,0,30)C.(-30,20,30)D.(2,20,3)
[单选题] 针对程序段:IF( A||B||C )THEN W=W/X,对于(A,B,C)的取值,(57)测试用例能够满足MCDC(修正条件逻辑判定)的要求。(57)A.(F,T,T) (T,F,T) (T,F,F) (T,T,F)B.(T,F,F) (T,T,F) (F,T,T) (F,F,F)C.(T,F,F) (T,T,F) (F,T,T) (F,F,T)D.(T,F,F) (F,T,F) (F,F,T) (F,F,F)
[单选题]针对下列程序段,对于(A,B,C)的取值,以下(56)测试用例组合能够满足语句覆盖的要求。 IF((A+10)=2 OR(B-20)<3)THENC=0 IF((A+30)=10 AND(C-30)<0)THEN B=30A.(2,30,1)B.(-20,0,30)C.(30,20,30)D.(2,20,3)
[单选题]针对程序段:IP(A||B||C) THEN W=W/X,对于(A,B,C)的取值,(57)测试用例能够满足MCDC(修正条件逻辑判定)的要求。A.(F,T,T)(T,F,T)(T,F,F)(T,T,F)B.(T,F,F)(T,T,F)(F,T,T)(F,F,F)C.(T,F,F)(T,T,F)(F,T,T)(F,F,T)D.(T,F,F)(F,T,F)(F,F,T)(F,F,F)
[单选题]针对程序段:IF(X>10)AND(Y<20)THEN W=W/A,对于(X,Y)的取值,以下(56)组测试用例能够满足判定覆盖的要求。A.(30,15)(40,10)B.(3,0)(30,30)C.(5,25)(10,20)D.(20,10)(1,100)