A.1,2,3,4,5,
B.2,3,4,5,6,
C.3,4,5,6,7,
D.2,3,4,5,1
[单选题]有以下程序prt(int *m,int n){ int i; for(i=0;i<n;i++) m[i]++;}main(){ int a[]={1,2,3,4,5},i; prt(a,5); for(i=0;i<5;i++) printf("%d,",a[i]);}程序运行后的输出结果是A.1,2,3,4,5, B.3,4,5,6,7,C.2,3,4,5,6, D.2,3,4,5,1,
[单选题]有以下程序: prt(int*m,int n) { int i; for(i=0;i<n;i++)m[i])++; } main() { int a[]={1,2,3,4,5},i; prt(a,5); for(i=0;i<5;i++) printf("%d,",a[i]); } 程序运行后的输出结果是 ______。A.1,2,3,4,5,B.2,3,4,5,6,C.3,4,5,6,7,D.2,3,4,5,1,
[单选题]有以下程序:fun(int a[],int m,int n){int i;for(i=m;i<n;i++)a[i+1]=a[i]+3;return a[i+1];}void main(){int i,a[6]={2,4,6,8,10,12};fun(a,2,5);for(i=0;i<6;i++)printf("%d",a[i]);}程序运行后输出的结果是( )。A.24691315 B.24691215 C.249121518 D.249121415
[主观题](9)有以下函数void prt(char ch,int n){ int i;for(i=1;i<=n;i++)printf(i%6!=0?"%c":"%c/n",ch);}执行调用语句prt('*',24);后,函数共输出了 (9) 行*号。
[单选题]有以下程序 vold soru(int a[], int n) { int i,i,t; for(i=0;i<n-1;i++) for(j=i+1;j<n;j++) if(a[i]<a[j]) { t=a[i]; a[i]=a[i]; a[j]=t; } } main() { int aa[10]={1,2,3,4,5,6,7,8,9,10),i; sore(aa+2, 5); for(i=0;i<10;i++) printf("%d,",aa[i]); printf("/n"); }
[单选题]有以下程序: void sort(int a[],int n) { int i,j,t; for(i=0;i<n;i++) for(j=i+1;<n;j++) if(a[i]<a[j]){ t=a[i]; a[i]=a[j]; a[j]=t; } } main() {int aa[10]={1,2,3,4,5,6,7,8,9,10},i; sort(aa+2,5); for(i=0;i<10;i++)printf("%d,",aa [i]); printf("/n"); } 程序运行后的
[单选题]有以下程序 void sort(int a[ ],int n) { int i,j,t; for(i=0;i<n-1;i+=2) for(j=i+2;j<n;j+=2) if(a[i]<a[j]) { t=a[i];a[i]=a[j];a[j]=t;} } main ( ) { int aa[10]={1,2,3,4,5,6,7,8,9,10},i; sort(aa,10); for(i=0;i<10;i++) printf(“%d”,aa[i]); printf(“/n”);} 其输出结果是(
[单选题]有以下程序fun(int *a,int n) { int i,j=0,p; p=j; for(i=j;i<n;i++) if(a[i]<a[p]) ____; return(p);}在下画线处应填入的是A.i=p B.a[p]=a[i] C.p=j D.p=i
[单选题]有以下程序: void sort(int a[], int n) {int i,j,t; for(i=0;i<n-1;i++) for(j=i+1;j<n;j++) if(a[i]<a[j]) { t=a[i]; a[i]=a[j]; a[j]=t; } } main() { int aa[10]={1,2,3,4,5,6,7,8,9,10},i; sort(aa+2,5); for(i=0;i<10;i++)printf("%d,",aa[i]); printf("/n"); } 程序
[单选题]有以下程序fun(int x,int y){static int m=0,i=2;i+=m+1;m=i+x+y;return m;}main(){int j=1,m=1,k;k=fun(j,m);printf("%d,",k);k=fun(j,m);printf("%d/n",k);}执行后的输出结果是()A . 5,5B . 5,11C . 11,11D . 11,5