漂洗piǎo xǐ

设(x)=sin x, 则(dfrac (pi )(2))= __-|||-_.-|||-A cos dfrac (pi )(2)-|||-B o-|||-C-

(int )_(-pi )^pi sqrt ({pi )^2-(x)^2}dx= )(int )_(-pi )^pi sqrt ({pi )^2-(x)^2}d

[名词解释] 瞟眇piǎo miǎo

lim_(xtoinfty)(pi)/(x)sin(pi x)=填空题（共40题，64.0分） 43. (1.6分) $\lim_{x\to\infty}\fr

[名词解释] 饿殍â piǎo

(15) lim _(xarrow pi )dfrac (sin 2(x-pi ))(x-pi );

设 (x)=pi x+(x)^2 pi leqslant xlt pi 以2π为周期,当f (x)在 [ -pi ,pi ) 上的傅立叶级数为-|||-dfr

[名词解释] 饿殍/饿莩 â piǎo

[名词解释] 瞟见piǎo jiàn

[名词解释] 剽悍piāo hàn