[单选题]

某病人血肌酐88.4μmol/L,尿肌酐浓度4420μmol/L,24h尿量为1584ml,其内生肌酐清除率Ccr为{Ccr=[尿肌酐浓度(μmol/L)×每分钟尿量(ml/min)]/血浆肌酐浓度μmol/L}

A.25ml/min

B.50ml/min

C.55ml/min

D.75ml/min

E.155ml/min

参考答案与解析: