(2)lim_(ntoinfty)cos(x)/(2)cos(x)/(4)...cos(x)/(2^n).

lim_(xtoinfty)(cos x)/(x^2)=A. ∞B. 1C. 0D. 不存在

cos dfrac (x)({2)^n})（提示：lim _(xarrow infty )(cos dfrac (x)(2)cos dfrac (x)(4)co

求极限lim_(xto0)(xsin x+2cos x-2)/(x^2)-x^(2cos x).2. 求极限$\lim_{x\to0}\frac{x\sin x

(2)lim_(xtoinfty)(x^2+cos^2x-1)/((x+sin x)^2)(2)$\lim_{x\to\infty}\frac{x^{2}+\c

5.当0≤x≤(pi)/(2)时，lim_(ntoinfty)sqrt[n](sin^nx+cos^nx)=____.5.当0≤x≤$\frac{\pi}{2}

(5)lim_(xto(pi)/(2))(1+cos x)^2sec x(5)$\lim_{x\to\frac{\pi}{2}}(1+\cos x)^{2\se

(8)lim_(xto2^+)(cos xcdotln(x-2))/(ln(e^x)-e^(2));(8)$\lim_{x\to2^{+}}\frac{\cos

(12)[2012，三]求极限lim_(xto0)(e^x^(2)-e^2-2cos x)/(x^4).(12)[2012，三]求极限$\lim_{x\to0}

8.设lim_(x to 0) (sin 2x + xf(x))/(x^3) = 1,则lim_(x to 0) (2cos x + f(x))/(x^2) =

计算极限lim _(xarrow 0)dfrac (xsin x+2cos x-2)({x)^2-(x)^2cos x}。计算极限。