. _(Y)(y)=dfrac (1)(2sqrt {2pi )}(e)^-dfrac (y{2)} ,gt 0-|||-bigcirc ._(Y)(y)=dfrac (1)(sqrt {2pi )}(e)^-dfrac (y{2)}(y)^-dfrac (1{2)} gt 0

参考答案与解析：

相关试题

=dfrac (T)(2pi )leqslant [ t] =dfrac ([ O] )(2);-|||-_(2)(A)_(1)+dfrac ({M)_(y)}({N)_(y)}sqrt ({{M)_

=dfrac (T)(2pi )leqslant [ t] =dfrac ([ O] )(2);-|||-_(2)(A)_(1)+dfrac ({M)_(y)}

  • 查看答案

    • (B) dfrac (9)(2pi {c)_(0)(y)^2} - y↑-|||-(0,y)-|||-+q-|||-(C) dfrac (qa)(2pi {varepsilon )_(0)(y)^3}

    (B) dfrac (9)(2pi {c)_(0)(y)^2} - y↑-|||-(0,y)-|||-+q-|||-(C) dfrac (qa)(2pi {va

  • 查看答案

    • (B) dfrac (9)(2pi {c)_(0)(y)^2} - y 个-|||-P(0,y)-|||-+q-|||-(C) dfrac (qa)(2pi {varepsilon )_(0)(y)^

    (B) dfrac (9)(2pi {c)_(0)(y)^2} - y 个-|||-P(0,y)-|||-+q-|||-(C) dfrac (qa)(2pi {

  • 查看答案

    • sqrt (2)pi -|||-C. dfrac (sqrt {2pi )}(4)-|||-D. dfrac (sqrt {2pi )}(8)

    sqrt (2)pi -|||-C. dfrac (sqrt {2pi )}(4)-|||-D. dfrac (sqrt {2pi )}(8)

  • 查看答案

    • 设(X,Y)的分布函数为(x,y)=dfrac (1)({pi )^2}(dfrac (pi )(2)+arctan dfrac (x)(2))(dfrac (pi )(2)+arctan y)，求：

    设(X,Y)的分布函数为(x,y)=dfrac (1)({pi )^2}(dfrac (pi )(2)+arctan dfrac (x)(2))(dfrac (

  • 查看答案

    • 设 y = y ( x ) 满足 +dfrac (1)(2sqrt {x)}y=2+sqrt (x), y(1)=3,求 y = y ( x ) 的渐近 线

    设 y = y ( x ) 满足 +dfrac (1)(2sqrt {x)}y=2+sqrt (x), y(1)=3,求 y = y ( x ) 的渐近 线设y

  • 查看答案

    • (B) (mu ,dfrac (1)(sqrt {2pi )})-|||-(C) (mu ,dfrac (1)(2)), (D)(0,σ).

    (B) (mu ,dfrac (1)(sqrt {2pi )})-|||-(C) (mu ,dfrac (1)(2)), (D)(0,σ).

  • 查看答案

    • dfrac (2pi )(sqrt {3)} D. dfrac (pi )(6)

    dfrac (2pi )(sqrt {3)} D. dfrac (pi )(6)

  • 查看答案

    • dfrac (2pi )(sqrt {3)}-|||-D. dfrac (pi )(6)

    dfrac (2pi )(sqrt {3)}-|||-D. dfrac (pi )(6)

  • 查看答案

    • 求下列函数的自然定义域：(1)y=sqrt(3x+2)；(2)y=dfrac(1)(1-{x)^2}；(3)y=dfrac(1)(x)-sqrt(1-(x)^2)；(4)y=dfrac(1)(sqrt

    求下列函数的自然定义域：(1)y=sqrt(3x+2)；(2)y=dfrac(1)(1-{x)^2}；(3)y=dfrac(1)(x)-sqrt(1-(x)^2

  • 查看答案