lim _(xarrow 0)dfrac (sin 2x-2sin x)(x(sqrt [3]{1+{x)^2}-1)}..
1.求下列极限:-|||-(1) lim _(xarrow 0)dfrac (sin 2x)(x);-|||-(3) lim _(xarrow dfrac {p
计算下列极限lim _(xarrow 0)(x)^2sin dfrac (1)(x)lim _(xarrow 0)(x)^2sin dfrac (1)(x)计算
lim _(xarrow 0)dfrac ({x)^2sin dfrac (1)(x)}(tan x)=A.0B.1C.lim _(xarrow 0)dfrac
lim _(xarrow 0)dfrac (sin x-tan x)((sqrt [3]{1+{x)^2}-1)(sqrt (1+sin x)-1)}= __
若lim _(xarrow 0)dfrac ({(1+a{x)^2)}^sin x-1}({x)^3}=6-|||-__,则lim _(xarrow 0)dfr
[题目] lim _(xarrow 0)dfrac (sin x-tan x)((sqrt [3]{1+{x)^2}-1)(sqrt (1+sin x)-1)}
(4) lim _(xarrow 0)dfrac (sin x-tan x)((sqrt [3]{1+{x)^2}-1)(sqrt (1+sin x)-1)}
(10) lim _(xarrow 0)dfrac (tan x-sin x)((sqrt [3]{1+{x)^2}-1)(sqrt (1+sin x)-1)}
3.求下列极限:-|||-(1) lim _(xarrow 0)sqrt ({x)^2-2x+5} ;-|||-(4 lim _(xarrow 0)dfrac