一列简谐波，已知(}_{3)^1=(x)_(2)处的质点的振动方程为(}_{3)^1=(x)_(2)，波是沿着(}_{3)^1=(x)_(2)轴正方向传播的，波速为(}_{3)^1=(x)_(2)，则此列简谐波的方程形式为：A.(}_{3)^1=(x)_(2)B.(}_{3)^1=(x)_(2)C.(}_{3)^1=(x)_(2)D.(}_{3)^1=(x)_(2)

一平面简谐波沿x轴负方向传播-|||-已知 =-1m 处质点的振动方-|||-程为 _(1)=Acos (omega t+phi ), 则-|||-x=2m 处

1.已知方程组 ) (x)_(1)+(x)_(2)+(x)_(3)+(x)_(4)=2 3(x)_(1)+2(x)_(2)+(x)_(3)+(x)_(4)=a

解方程组： ) (x)_(1)-(x)_(2)-(x)_(3)=2 2(x)_(1)-(x)_(2)-3(x)_(3)=1 3(x)_(1)+2(x)_(2)

[单选题]一平面简谐波沿X轴正向传播，已知x=1（1<λ）处质点的振动方程为y=Acoswt+φ0），波速为u，那么x=0处质点的振动方程为：（）A . y=Acos［w（t+1/u）+φ0］B . y=ACOS［w（t-1/u）+φ0］C . y=Acos［wt+1/u+φ0］D . y=Acos［wt-1/u+φ0］

3.已知方程组 ) (x)_(1)+(x)_(2)+2(x)_(3)=a 3(x)_(1)-(x)_(2)-6(x)_(3)=a+2 (x)_(1)+4(x

9.已知方程组如下-|||- ) (x)_(1)-(x)_(2)=1, -(x)_(1)+(x)_(2)=2, 2(x)_(1)-2(x)_(2)=3, -3

用列主元消去法解方程组 ) 3(x)_(1)-(x)_(2)+4(x)_(3)=1 -(x)_(1)+2(x)_(2)-9(x)_(3)=0 -4(x)_(1

用克莱姆法则求解方程组 ) (x)_(1)-(x)_(2)-(x)_(3)=-1 -2(x)_(1)+2(x)_(2)+(x)_(3)=1 2(x)_(1)-

一平面简谐波沿x轴正方向传播，波速u=2 m/s，已知在x=0处的质点的振动方程为 y=0.1cos(2pt) (SI)，该波的波函数为A. y=0.1cos(

已知线性方程组 ) a(x)_(1)+(x)_(3)=1 (x)_(1)+a(x)_(2)+(x)_(3)=0 (x)_(1)+2(x)_(2)+a(x)_(