1.计算下列定积分:-|||-(1) (int )_(dfrac {pi )(3)}^pi sin (x+dfrac (pi )(3))dx ;-|||-(2) (int )_(-2)^1dfrac (dx)({(11+5x))^3}-|||-(3)∫_2^2 sinφcos3φdφ;-|||-(4) (int )_(0)^pi (1-(sin )^3theta )dtheta -|||-(5) (int )_(dfrac {pi )(6)}^dfrac (pi {2)}(cos )^2udu-|||-(6) (int )_(0)^sqrt (2)sqrt (2-{x)^2}dx ;-|||-(7) (int )_(-sqrt {2)}^sqrt (2)sqrt (8-2{y)^2}dy =-|||-(8) (int )_(dfrac {1)(sqrt {2)}}^1dfrac (sqrt {1-{x)^2}}({x)^2}dx =-|||-(9) (int )_(0)^a(x)^2sqrt ({a)^2-(x)^2}dx(agt 0) ;-|||-(10) (int )_(1)^sqrt (3)dfrac (dx)({x)^2sqrt (1+{x)^2}}-|||-(11) (int )_(-1)^1dfrac (xdx)(sqrt {5-4x)} =-|||-(12) (int )_(1)^4dfrac (dx)(1+sqrt {x)} =-|||-(13) (int )_(dfrac {3)(4)}^1dfrac (dx)(sqrt {1-x)-1} =-|||-(14) (int )_(0)^sqrt (2a)dfrac (xdx)(sqrt {3{a)^2-(x)^2}}(agt 0)-|||-(15) (int )_(0)^1t(e)^-dfrac (12{2)d}t =-|||-(16) (int )_(1)^(e^2)dfrac (dx)(xsqrt {1+ln x)}-|||-(17) (int )_(-2)^0dfrac ((x+2)dx)({x)^2+2x+2} =-|||-(18) (int )_(0)^2dfrac (xdx)({({x)^2-2x+2)}^2}-|||-(19) (int )_(-pi )^pi (x)^4sin xdx =-|||-(20)[^2 44cos^4θdθ;-|||-(21) (int )_(-dfrac {1)(2)}^dfrac (1{2)}dfrac ({(arcsin x))^2}(sqrt {1-{x)^2}}dx-|||-(22) (int )_(-5)^5dfrac ({x)^3(sin )^2x}({x)^4+2(x)^2+1}dx1.计算下列定积分:-|||-(1) (int )_(dfrac {pi )(3)}^pi sin (x+dfrac (pi )(3))dx ;-|||-(2) (int )_(-2)^1dfrac (dx)({(11+5x))^3}-|||-(3)∫_2^2 sinφcos3φdφ;-|||-(4) (int )_(0)^pi (1-(sin )^3theta )dtheta -|||-(5) (int )_(dfrac {pi )(6)}^dfrac (pi {2)}(cos )^2udu-|||-(6) (int )_(0)^sqrt (2)sqrt (2-{x)^2}dx ;-|||-(7) (int )_(-sqrt {2)}^sqrt (2)sqrt (8-2{y)^2}dy =-|||-(8) (int )_(dfrac {1)(sqrt {2)}}^1dfrac (sqrt {1-{x)^2}}({x)^2}dx =-|||-(9) (int )_(0)^a(x)^2sqrt ({a)^2-(x)^2}dx(agt 0) ;-|||-(10) (int )_(1)^sqrt (3)dfrac (dx)({x)^2sqrt (1+{x)^2}}-|||-(11) (int )_(-1)^1dfrac (xdx)(sqrt {5-4x)} =-|||-(12) (int )_(1)^4dfrac (dx)(1+sqrt {x)} =-|||-(13) (int )_(dfrac {3)(4)}^1dfrac (dx)(sqrt {1-x)-1} =-|||-(14) (int )_(0)^sqrt (2a)dfrac (xdx)(sqrt {3{a)^2-(x)^2}}(agt 0)-|||-(15) (int )_(0)^1t(e)^-dfrac (12{2)d}t =-|||-(16) (int )_(1)^(e^2)dfrac (dx)(xsqrt {1+ln x)}-|||-(17) (int )_(-2)^0dfrac ((x+2)dx)({x)^2+2x+2} =-|||-(18) (int )_(0)^2dfrac (xdx)({({x)^2-2x+2)}^2}-|||-(19) (int )_(-pi )^pi (x)^4sin xdx =-|||-(20)[^2 44cos^4θdθ;-|||-(21) (int )_(-dfrac {1)(2)}^dfrac (1{2)}dfrac ({(arcsin x))^2}(sqrt {1-{x)^2}}dx-|||-(22) (int )_(-5)^5dfrac ({x)^3(sin )^2x}({x)^4+2(x)^2+1}dx


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