方程组 _(1)-3(x)_(2)+(x)_(3)=2 有不同的向量解, _(1)-3(x)_(2)+(x)_(3)=2 _(1)-3(x)_(2)+(x)_(3)=2则()

方程组       有不同的向量解,

            

            

则()

A.t = -1 

B.t = 2 

C.t = 1 

D.t = 0

参考答案与解析:

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