(sin x)=dfrac (1)({cos )^2x} in (0,dfrac (pi )(2)),则(sin x)=dfrac (1)({cos )^2x}
(3) lim _(xarrow 0)dfrac (1-cos 3x)({sin )^2x}
[题目] lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})= __
[题目]求 lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})
[题目]求 lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})
求极限lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})= ()求极限
)int dfrac (1)({cos )^2x(sin )^2x}dx.
(15)lim _(xarrow 0)dfrac (1-cos 2x)(xsin x)(15)
(3) lim _(xarrow 0)dfrac (1-cos 2x)(xsin x) ()-|||-__
(4) lim _(xarrow 0)dfrac (1-cos 2x)(xsin x) =