A. 若 a=1 ，则 a_{1},a_{2},a_{3} 线性相 关
B. 若 a=0 ，则 a_{1},a_{2},a_{3} 线性相 关
C. 若 a=0 ，则a a_{3} 可由a1,a a_{1},a_{2} _线 性表出,且表示方式不唯一
D. 若 a \neq 0 ，则， a_{1},a_{2},a_{3} 线性相 关
14.设 (alpha )_(1)=(1,-1,2,4) (alpha )_(2)=(0,3,1,2), (alpha )_(3)=(3,0,7,14), (a
13.单选题若alpha_(1)=(1-1 2),alpha_(2)=(-2 1 0),alpha_(3)=(-1 0 t)线性相关,则()A. t=-2B.
设向量组 (alpha )_(1)=((0,1,1))^T, (alpha )_(2)=((1,0,1))^T (alpha )_(3)=((2,1,0))^T
已知向量组(alpha )_(1)=(1,0,2,0), (alpha )_(2)=(0,-1,1,2), (alpha )_(3)=(1,-2,4,4)(al
设向量组alpha_(1)=(1,-1,2,4),alpha_(2)=(0,3,1,2),alpha_(3)=(3,0,7,14),alpha_(4)=(1,-
设向量(alpha )_(1)=((1,1,-1))^T (alpha )_(2)=((0,2,1))^T,(alpha )_(1)=((1,1,-1))^T
已知(alpha )_(1)=((1,1,2,2))^T, (alpha )_(2)=((1,-1,4,0))^T (alpha )_(3)=((1,0,3,1
向量方程((a)_(1)+alpha )-7((alpha )_(2)+alpha )+4(alpha )_(3)=0，其中((a)_(1)+alpha )-7
设3阶矩阵Q=(matrix(1 & 2 & 3 cr 2 & 4 & t cr 3 & 6 & 9))，P为3阶非零矩阵，且PQ=0，则( )A. t=6时
设alpha =(dfrac (1)(2),0,0,dfrac (1)(2)) ,=E-(alpha )^Talpha =E+2(alpha )^Talpha