如图，入射波的波函数为=Acos (omega t-dfrac (2pi )(lambda )x)-|||-__ __，在=Acos (omega t-dfrac (2pi )(lambda )x)-|||-__ __ 处的P点发生反射，若经分界面反射的波的振幅和入射波的振幅相等，求(1)反射波的波函数=Acos (omega t-dfrac (2pi )(lambda )x)-|||-__ __;(2)驻波方程y; (3)OP间因入射波和反射波叠加而静止的各点的位置。=Acos (omega t-dfrac (2pi )(lambda )x)-|||-__ __

设入射波的表达式为-|||-_(1)=Acos (omega t-dfrac (2pi x)(lambda )).-|||-波在距原点 _(0)=dfrac (

设沿弦线传播的一入射波的表达式为_(1)=Acos (omega t-2pi dfrac (x)(lambda ))，波在_(1)=Acos (omega t-

9.沿着相反方向传播的两列相干波,其波动方程为 _(1)=Acos 2pi (vt-dfrac (x)(lambda )) _(2)=-|||-cos 2pi

设入射波的表达式为=Acos 2pi (dfrac (t)(T)+dfrac (x)(lambda ))-|||-__,在x=0处发生反射,反射点为一固定端,设

34-4 设入射波的表达式为 _(1)=Acos [ 2pi (dfrac (x)(lambda )+dfrac (t)(T))] , 在 x=0 处发生反射,

4.设入射波的表达式为 _(1)=Acos 2pi (dfrac (x)(lambda )+dfrac (t)(T)), 在 x=0 处发生反射,反射点为 --

(3109)设入射波的表达式为_(1)=Acos 2pi (dfrac (x)(lambda )+dfrac (t)(T)),在x = 0处发生反射,反射点为一

设入射波为 _(1)=Acos 2pi (t/T-x/lambda ) ,在 x=0 处反射,反射点为一自由端。求合成-|||-驻波的(1)表达式;(2)波节位

πm·s^(-1))=dfrac (dy)(dt)=Rtdfrac (2pi )(T)cos dfrac (2pi )(T)ti+ndfrac (2pi )(T

(B) dfrac (lambda )(2pi {varepsilon )_(0)a}. (C) dfrac (lambda )(4pi {varepsilon