原式为：lim _(xarrow 0)(dfrac (1)({e)^x-1}-dfrac (1)(ln (1+x)))= )=

[题目 lim _(xarrow 0)dfrac (ln {(1+x))^dfrac (1{x)-1}}(x)

计算：lim _(xarrow 0)dfrac ({(1+x))^dfrac (2{x)}-(e)^2(1-ln (1+x))}(x)。计算：。

lim _(xarrow 1)(dfrac (x)(x-1)-dfrac (1)(ln x))-|||-__ __

lim _(xarrow 1)(dfrac (x)(x-1)-dfrac (1)(ln x))-|||-__ __

〔此题总分值10分〕求极限lim _(xarrow 0)((dfrac {ln (1+x))(x))}^dfrac (1{{e)^x-1}} ()〔此题总分值1

〔此题总分值10分〕求极限lim _(xarrow 0)((dfrac {ln (1+x))(x))}^dfrac (1{{e)^x-1}} ()〔此题总分值1

[题目] lim _(xarrow 1)(dfrac (x)(x-1)-dfrac (1)(ln x))

lim _(xarrow 0)(dfrac (1)(x)-dfrac (1)({e)^x-1})-|||-__；；

lim _(xarrow 0)(dfrac (1)(x)-dfrac (1)({e)^x-1}) ()-|||-__ __

lim _(xarrow 0)(dfrac (1)(x)-dfrac (1)({e)^x-1}) ()-|||-__ __