微分方程^11-2(1-(tan )^2x)=0的通解为^11-2(1-(tan )^2x)=0A.^11-2(1-(tan )^2x)=0B.^11-2(1-(tan )^2x)=0C.^11-2(1-(tan )^2x)=0D.^11-2(1-(tan )^2x)=0

(4) lim _(xarrow 0)((1+3{tan )^2x)}^(cot ^2x);

lim _(xarrow 0)dfrac (1-{e)^(x^2)}(xsin 2x)

lim _(xarrow 0)dfrac ({(1+2{x)^2)}^dfrac (3{2)}-1}(tan 2x(cos sqrt {x)-1)}。。

5.求极限 lim _(xarrow 0)dfrac ({tan )^2x-(x)^2}({x)^2(tan )^2x}

【题目】-|||-计算下列极限:-|||-lim _(xarrow 0)((1+3{tan )^2x)}^(cot ^2x) .

已知f(x)=(2x)/(sqrt (1-{x)^2)}，则(df(sqrt (1-{x)^2)})/(dx)=(,,,,,)A、-2；B、-dfrac(2x)

11.求极限lim_(xto0)(e^x-cos x)/(tan 2x)11.求极限$\lim_{x\to0}\frac{e^{x}-\cos x}{\tan

(2) lim _(xarrow 0)[ dfrac (1)(ln (1+{tan )^2x)}-dfrac (1)(ln (1+{x)^2)}]

(2) lim _(xarrow 0)[ dfrac (1)(ln (1+{tan )^2x)}-dfrac (1)(ln (1+{x)^2)}]

微分方程^3dx+(2x(y)^2-1)dy=0的通解为 A ^3dx+(2x(y)^2-1)dy=0（^3dx+(2x(y)^2-1)dy=0 为任意常数）B