已知曲线积分
当
0" data-width="50" data-height="20" data-size="795" data-format="png" style="max-width:100%">时与路径无关,
(1)求常数
(2)求
,使得
已知曲线积分
当
0" data-width="50" data-height="20" data-size="795" data-format="png" style="max-width:100%">时与路径无关,
(1)求常数
(2)求
,使得
(int )_(0)^dfrac (pi {4)}dfrac (x)(1+cos 2x)dx=( ) .(int )_(0)^dfrac (pi {4)}dfr
int dfrac (sin x)(1+{cos )^2x}dx=-|||-__
计算不定积分int dfrac (2cos dfrac {1)(x)}({x)^2}dx计算不定积分
(int )_(-dfrac {pi )(2)}^dfrac (pi {2)}((cos )^2x+dfrac (xcos x)(1+{cos )^2x})dx
(int )_(-dfrac {pi )(2)}^dfrac (pi {2)}dfrac (|x|sin x)(1+{cos )^3x}dx=(int )_(-
(sin x)=dfrac (1)({cos )^2x} in (0,dfrac (pi )(2)),则(sin x)=dfrac (1)({cos )^2x}
int dfrac (cos 2x)(cos x+sin x)dx
计算int dfrac (dx)(cos x(1+sin x))计算
.int dfrac (1+{cos )^2x}(1+cos 2x)dx
)int dfrac (1)({cos )^2x(sin )^2x}dx.