lim _(xarrow dfrac {pi )(2)}dfrac (cos x)(pi -2x).

计算 lim _(xarrow dfrac {pi )(2)}dfrac (ln sin x)({(pi -2x))^2}

求lim _(xarrow dfrac {pi )(2)}dfrac (ln sin x)({(pi -2x))^2}求

1.求下列极限:-|||-(1) lim _(xarrow 0)dfrac (sin 2x)(x);-|||-(3) lim _(xarrow dfrac {p

(sin x)=dfrac (1)({cos )^2x} in (0,dfrac (pi )(2)),则(sin x)=dfrac (1)({cos )^2x}

1.求下列极限：（2）lim _(xarrow dfrac {pi )(2)}dfrac (ln sin x)({(pi -2x))^2}1.求下列极限：（2）

(int )_(-dfrac {pi )(2)}^dfrac (pi {2)}((cos )^2x+dfrac (xcos x)(1+{cos )^2x})dx

(int )_(0)^dfrac (pi {4)}dfrac (x)(1+cos 2x)dx=( ) .(int )_(0)^dfrac (pi {4)}dfr

lim _(xarrow dfrac {pi )(2)}((1+cos x))^3sec x;

(15) lim _(xarrow pi )dfrac (sin 2(x-pi ))(x-pi );

[题目] lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})= __