dfrac (1)(2)pi (R)^2E-|||-D. sqrt (2)(R)^2E-|||-E. dfrac (pi {R)^2E}(sqrt {2)}
dfrac (3)(2)RC dfrac (7)(2)R D. dfrac (3)(2)RT对于双原子气体的摩尔定压热容的表达式为()
dfrac (pi {R)^2E}(2)-|||-C.2πR^2E-|||-D.0
已知氢原子的 (varphi )_(2{p)_(2)}=dfrac (1)(4sqrt {2pi {{a)_(0)}^3}}(dfrac (r)({a)_(0)
dfrac ({U)_(0)I}(2R)-|||-D . dfrac ({U)_(0)I}(2pi R)
^circ -dfrac (4)(2)-|||-:^circ +dfrac ({varphi )^1}(2) D. ^circ -dfrac ({varphi
_(1)lt rlt (R)_(2) =dfrac ({Q)_(1)}(4{{Te)_(0)(r)^2}}-|||-D.两球面间的电势差 Delta U=dfr
dfrac ({mu )_(0)I}(pi R)(dfrac (1)(2)+dfrac (pi )(6))-|||-dfrac ({mu )_(0)I}(pi
7.设 (x,y)=dfrac (1)(xy),r=sqrt ({x)^2+(y)^2} _(1)= (x,y)|(x,y)in {R)^2 dfrac (1)
[问答题]设有向量组α1,α2,…,αr(r>1).β1=α2+α3+…+αr,β2=α1+α3+…+αr,…,βr=α1+α2+…+αr-1,证明:向量组α1