3.验证极lim _(xarrow 0)dfrac ({x)^2sin dfrac (1)(x)}(sin x)存在，但不能用洛必达法则得出.

2.验证极限lim _(xarrow 0)dfrac ({x)^2sin dfrac (1)(x)}(sin x)存在,但不能用洛必达法则得出.2.验证极限存在

2.验证极限lim _(xarrow infty )dfrac (x+sin x)(x)存在，但不能用洛必达法则得出。2.验证极限存在，但不能用洛必达法则得出。

lim _(xarrow 0)dfrac ({x)^2sin dfrac (1)(x)}(tan x)=A.0B.1C.lim _(xarrow 0)dfrac

1.用洛必达法则求下列极限.-|||-(1) lim _(xarrow 0)dfrac (ln (1+x))(x) :-|||-(3) lim _(xarrow

计算下列极限lim _(xarrow 0)(x)^2sin dfrac (1)(x)lim _(xarrow 0)(x)^2sin dfrac (1)(x)计算

题目：1.用洛必达法则求下列极限:-|||-(1) lim _(xarrow 0)dfrac ({e)^x-cos x}(sin x)-|||-(2) lim

3.计算下列极限:-|||-(1) lim _(xarrow 0)(x)^2sin dfrac (1)(x); ()-|||-__

1.用洛必达法则求下列极限:-|||-(1) lim _(xarrow 0)dfrac (ln (1+x))(x)-|||-(4) lim _(xarrow p

计算下列极限：(1) lim _(xarrow 0)(x)^2sin dfrac (1)(x);-|||-(2) lim _(xarrow infty )dfr

lim _(xarrow 0)dfrac (sin 4x)(sin x)= )-|||-__lim _(xarrow 0)dfrac (sin 4x)(sin