初等变换解下列方程组 2x+3y+z=4 x-2y+4z=-5 3x+8y-2z=13 4x-y+9z=-6
解:UNDUND次UNDUND方UND组 ) 2x+3y+z=4 x-2y+4z=-5 3x+8y-2z=13 4x-y+9z=-6 .
2x+3y+Z=4X-2y+4z=-5(2)3x+8y-2z=134x-y+9z=-62x+3y+Z=4X-2y+4z=-5(2)3x+8y-2z=134x-y
(x,y,z)=(x)^3+4(y)^3+4(z)^2,则(x,y,z)=(x)^3+4(y)^3+4(z)^2()。(x,y,z)=(x)^3+4(y)^3+
用克莱姆法则解下列方程组:-|||-2) ) x+y+z=0 x+2y+3z=-1 x+3y+6z=0 .
用克莱姆法则解下列线性方程组:-|||-(3) ) x+y-2z=-3 5x-2y+7z=22 2x-5y+4z=4 .
用克莱姆法则解下列线性方程组:(1) ) x+y-2z=-3 5x-2y+7z=22 2x-5y+4z=4 .用克莱姆法则解下列线性方程组:(1)
用克拉默法则解方程组。2x+y-5z+w=8 x-3y-6w=9 2y-z+2w=-5 x+4y-...用克拉默法则解方程组。2x+y-5z+
(4) ) 2x+y-z+w=1 3x-2y+z-3w=4 x+4y-3z+5w=-2 .
2x+y-z+W=1(4){3x-2y+z-3w=4x+4y-3z+5w=-22x+y-z+W=1(4){3x-2y+z-3w=4x+4y-3z+5w=-2
[单选题]已知实数x,y,z满足x2+y2+z2-2x+4y-6z+14=0,则x+y+z=()。A . 2B . 3C . 4D . 5