



(B) pi +dfrac (4)(3) (C) pi +2 . (D) pi +dfrac (8)(3)
dfrac (pi )(4) C. dfrac (pi )(2) D.π
sqrt (2)pi :2 C. sqrt (2)pi :4 D. sqrt (2)pi :8
dfrac (1)(2)pi .-|||-C.π-|||-D. dfrac (5)(4)pi .-|||-0
化 tan dfrac (pi -C)(2)=-pi `D =dfrac (E+C)(2)=cotdfrac (4)(2)-|||-6三年 therefore
A (pi, 0, pi); B (-pi, pi, pi); C (0, 0, pi); D (-pi, 0, pi) 空间曲线 $\be
dfrac (q)(4pi varepsilon oR)-|||-C. dfrac (q)(4pi {varepsilon )_(0)(R)^2}-|||-D.
sqrt (2)pi -|||-C. dfrac (sqrt {2pi )}(4)-|||-D. dfrac (sqrt {2pi )}(8)
(B) dfrac (lambda )(2pi {varepsilon )_(0)a}. (C) dfrac (lambda )(4pi {varepsilon
=dfrac (Q)(4pi {varepsilon )_(0)r}-|||-(D) =dfrac (Q)(4pi {varepsilon )_(0)(r)^2