3.6 求下列差分方程所描述的LTI离散系统的零输入响应、零状态响应和全响应。-|||-(1) (k)-2y(k-1)=f(k),-|||-(k)=2g(k),y(-1)=-1-|||-(2) (k)+2y(k-1)=f(k),-|||-(k)=(2)^kg(k),y(-1)=1-|||-(3) (k)+2y(k-1)=f(k),-|||-(k)=(3k+4)g(k), y(-1)=-1-|||-(4) (k)+3y(k-1)+2y(k-2)=f(k),-|||-(k)=g(k),y(-1)=1,y(-2)=0-|||-(5) (k)+2y(k-1)+y(k-2)=f(k),-|||-(k)=3((dfrac {1)(2))}^kg(k), (-1)=3, y(-2)=-5

3.6 求下列差分方程所描述的LTI离散系统的零输入响应零状态响应和全响应。-|||-(1) (k)-2y(k-1)=f(k),-|||-(k)=2g(k),y

3.6 求下列差分方程所描述的LTI离散系统的零输入响应、零状态响应和全响应。-|||-(1) (k)-2y(k-1)=f(k),-|||-f(k)=2g(k)

1-|||-2-|||-2-|||-3 square -|||-4-|||-(a) (b)-|||-f(k)+ y(k) f(k) + ② 2 + y(k)-|

-皆齐次线性方程组 2x+(k-1)y=0 有非零解,则 k= ()-|||-2或 -1-|||-B-|||--2 或 -1-|||-C -2 或1-|||-D

).，求：（1）参数a； X=k =dfrac (a)({2)^k}(k=1,2,... ).； X=k =dfrac (a)({2)^k}(k=1,2,...

已知x_(1)[k]=-1,1,0,2,1,0,-1，x_(2)[k]=1,2,3,-1,-1,-1,-1，画出下列离散序列的波形。(1) y_(1)[k]=x

3.11各序列的图形如题3.11图所示,求下列卷积和。-|||-(1) _(1)(k)*(f)_(2)(k)-|||-(2) _(2)(k)*(f)_(3)(k

（1）设随机变量X的分布律为 X=k =lambda ((1-lambda ))^k-1 =1, 2,...，其中 X=k =lambda ((1-lambda

_(1)+({k)_(2)}^2=({k)_(3)}^theta -|||-D. _(1)times ({k)_(2)}^theta =({k)_(3)}^th

+(k)_(n-1)+(I)_(n-1)+1-|||-其中 _(1)+(k)_(2)+... +(k)_(n-r+1)=1.