(2)设样本X1,X2,···,X5来自总体N (0,1), =dfrac (C({X)_(1)+(X)_(2))}({({{X)_(3)}^2+({X)_(4
设样本X1,X2,X3,X4,X5来自总体N(0,1),设样本X1,X2,X3,X4,X5来自总体N(0,1),设样本X1,X2,X3,X4,X5来自总体N(0
4.(1)设样本X1,X2,···X6来自总体N(0,1), =(({X)_(1)+(X)_(2)+(X)_(3))}^2+((X)_(4)+-|||-_(5)
4.(1)设样本x1,x2,···,X6来自总体N(0,1), =(({X)_(1)+(X)_(2)+(X)_(3))}^2+((X)_(4)+-|||-_(5
15.设总体 approx N(0,1), (X1,X2,X3,X4,X5,X6)为样本,另设-|||-=(({X)_(1)+(X)_(2))}^2+(({X)
设总体X~ N(0,1),X1 , X2,…, X6为来自总体X的样本,=(({X)_(1)+(X)_(2)+(X)_(3))}^2+(({X)_(4)+(X)
10.设总体 sim N(0,1), X1,X2,X3是来自X的样本,则 =dfrac (sqrt {3)X}(sqrt {{{X)_(1)}^2+({X)_(
设x1,x2···,x5为来自总体x1,x2···,x5的样本,x1,x2···,x5,x1,x2···,x5,x1,x2···,x5与x1,x2···,x5分
5.设X1,X2,X3,X4是总体 sim N(0,1) 的简单随机样本,则 =dfrac (sqrt {3)(X)_(1)}(sqrt {{{X)_(2)}^
(5)设样本x1,x2,···,x 6来自总体N(0,1), =(({X)_(1)+(X)_(2)+(X)_(3))}^2+-|||-(({X)_(4)+(X)