+dfrac (1)({(2n-1))^2}(2n-1)x+... ] -|||-(B) dfrac (2)(pi )[ dfrac (1)({2)^2}sin
设((sin )^2x)=dfrac (x)(sin x),求((sin )^2x)=dfrac (x)(sin x) .设,求.
(sin x)=dfrac (1)({cos )^2x} in (0,dfrac (pi )(2)),则(sin x)=dfrac (1)({cos )^2x}
(int )_(-dfrac {pi )(2)}^dfrac (pi {2)}((cos )^2x+dfrac (xcos x)(1+{cos )^2x})dx
18.[单选题]-|||-2、高阶导数2-|||-.设 (x)=(sin )^4x-(cos )^4x ,则 ^(n)(x)= __-|||-A ^ncos (
函数(x)=sin (2x+dfrac (pi )(6))的最小正周期为 .函数的最小正周期为 .
函数(x)=sin (2x+dfrac (pi )(6))的最小正周期为___________ .10 . 函数的最小正周期为___________ .
[题目] lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})= __
求极限lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})= ()求极限
[题目]求 lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})