第西意 不定积分-|||-(20)f(f(m(m+x)/√(1+x))dx;-|||-(10) sqrt (tan sqrt {1+{x)^2}}cdot dfrac (x{d)^2}(sqrt {1+{x)^2}}-|||-(22) int dfrac (dx)(sin xcos x)-|||-(21) int dfrac (1+ln x)({(xln x))^2}dx;-|||-(24)∫cos^3xdx-|||-(23) int dfrac (ln tan x)(cos xsin x)dx;-|||-(26)∫sin22xcos3xdx;-|||-(25) int (cos )^2(omega t+varphi )dt;-|||-(28)|sin55xsin7xdx;-|||-(27) int cos xcos dfrac (x)(2)dx;-|||-(29) int (tan )^3xsec xdx;-|||-(30) int dfrac (dx)({e)^x+(e)^-x};-|||-(31) int dfrac (1-x)(sqrt {9-4{x)^2}}dx;-|||-(32) int dfrac ({x)^3}(9+{x)^2}dx;-|||-(33) int dfrac (dx)(2{x)^2-1};-|||-(34) int dfrac (dx)((x+1)(x-2));-|||-(35) int dfrac (x)({x)^2-x-2}dx;-|||-(36) int dfrac ({x)^2dx}(sqrt {{a)^2-(x)^2}}(agt 0);-|||-(37) int dfrac (dx)(xsqrt {{x)^2-1}};-|||-(38) int dfrac (dx)(sqrt {{({x)^2+1)}^3}}-|||-(39) int dfrac (sqrt {{x)^2-9}}(x)dx-|||-(40) int dfrac (dx)(1+sqrt {2x)};-|||-(41) int dfrac (bx)(1+sqrt {1-{x)^2}}-|||-(42) int dfrac (dx)(x+sqrt {1-{x)^2}};-|||-(43) int dfrac (x-1)({x)^2+2x+3}dx;-|||-(44) int dfrac ({x)^3+1}({({x)^2+1)}^2}dx.-|||-前面我们在复合函数求导法则的基础上,得到了换元积分法.-|||-个函数乘积的求导法则,来推得另一个求积分的基本方法-|||-设函数 u=u(x) 及 v=v(x) 具有连续导数,则两个函数乘积的-|||-(uv)'=u'v+uv',-|||-,得

参考答案与解析:

相关试题

求不定积分int dfrac (arctan sqrt {x)}(sqrt {x)(1+x)}dx

求不定积分int dfrac (arctan sqrt {x)}(sqrt {x)(1+x)}dx求不定积分

  • 查看答案
  • 第四章 不正积分-|||-(20) int dfrac (arctan sqrt {x)}(sqrt {x)(1+x)}dx-|||-(10) sqrt (100sqrt {1+{x)^2}cdot

    第四章 不正积分-|||-(20) int dfrac (arctan sqrt {x)}(sqrt {x)(1+x)}dx-|||-(10) sqrt (10

  • 查看答案
  • int tan sqrt (1+{x)^2}cdot dfrac (xdx)(sqrt {1+{x)^2}}

    int tan sqrt (1+{x)^2}cdot dfrac (xdx)(sqrt {1+{x)^2}}

  • 查看答案
  • (19) int tan sqrt (1+{x)^2}cdot dfrac (xdx)(sqrt {1+{x)^2}}-|||-(20) int dfrac (arctan sqrt {x)}(sqr

    (19) int tan sqrt (1+{x)^2}cdot dfrac (xdx)(sqrt {1+{x)^2}}-|||-(20) int dfrac (

  • 查看答案
  • (19) int tan sqrt (1+{x)^2}cdot dfrac (xdx)(sqrt {1+{x)^2}}-|||-(20) int dfrac (arctan sqrt {x)}(sqr

    (19) int tan sqrt (1+{x)^2}cdot dfrac (xdx)(sqrt {1+{x)^2}}-|||-(20) int dfrac (

  • 查看答案
  • 第四章 不正积分-|||-(20)arctan√x/dx;-|||-(10) sqrt (18sqrt {1+{x)^2}}cdot dfrac (xsqrt {x)}(sqrt {1+{x)^2}}

    第四章 不正积分-|||-(20)arctan√x/dx;-|||-(10) sqrt (18sqrt {1+{x)^2}}cdot dfrac (xsqrt

  • 查看答案
  • 求不定积分int dfrac (1)(2x)sqrt (ln x)dx=().int dfrac (1)(2x)sqrt (ln x)dx=int dfrac (1)(2x)sqrt (ln x)dx

    求不定积分int dfrac (1)(2x)sqrt (ln x)dx=().int dfrac (1)(2x)sqrt (ln x)dx=int dfrac

  • 查看答案
  • =(int )_(-1)^1(f(x)+f(-x)+x} cdot ln (sqrt (1+{x)^2}+x)dx.

    =(int )_(-1)^1(f(x)+f(-x)+x} cdot ln (sqrt (1+{x)^2}+x)dx..

  • 查看答案
  • 不定积分int dfrac (1)(1+sqrt {x)}dx= __ 。() int dfrac (1)(1+sqrt {x)}dx= __ 。

    不定积分int dfrac (1)(1+sqrt {x)}dx= __ 。() int dfrac (1)(1+sqrt {x)}dx= __ 。

  • 查看答案
  • 不定积分 int dfrac ({x)^2-1}(sqrt {xsqrt {x)}}dx=

    不定积分 int dfrac ({x)^2-1}(sqrt {xsqrt {x)}}dx=

  • 查看答案