总体sim N(0,1), X1,X2,X3,X4,X55,X6,X7,X8为来自总体sim N(0,1), X1,X2,X3,X4,X55,X6,X7,X8的样本，则统计量sim N(0,1), X1,X2,X3,X4,X55,X6,X7,X8 sim N(0,1), X1,X2,X3,X4,X55,X6,X7,X8

设样本X1,X2,X3,X4,X5来自总体N(0,1),设样本X1,X2,X3,X4,X5来自总体N(0,1),设样本X1,X2,X3,X4,X5来自总体N(0

设总体sim N(0,1) X1,X2,···,X6是来自总体X的简单随机样本sim N(0,1) X1,X2,···,X6分别为样本均值和样本方差sim N(

设总体sim N(0,1) ,X1,X2,···X5为来自总体的样本,令sim N(0,1) ,X1,X2,···X5则下列说法错误的是( )sim N(0,1

15.设总体 approx N(0,1), (X1,X2,X3,X4,X5,X6)为样本,另设-|||-=(({X)_(1)+(X)_(2))}^2+(({X)

5.设X1,X2,X3,X4是总体 sim N(0,1) 的简单随机样本,则 =dfrac (sqrt {3)(X)_(1)}(sqrt {{{X)_(2)}^

设总体X~ N(0,1),X1 , X2,…, X6为来自总体X的样本,=(({X)_(1)+(X)_(2)+(X)_(3))}^2+(({X)_(4)+(X)

22.设X1,X2,···,x6是来自总体N(0,1 )的样本,则 _(1)sim ()-|||-(A)N(0,1) (B)N(0,6) (C)x^2(1) (

设X1,X2,X3,X4,X5是来自正态总体X1,X2,X3,X4,X5的样本.(1) 求C使统计量X1,X2,X3,X4,X5服从X1,X2,X3,X4,X5

4.第六章4(1),设样本x1,x2 x1,x4,x4,x,来自总体N(0,1), =(({x)_(2)+(x)_(2)+(x)_(2))}^2+(({x)_(

4.(1)设样本x1,x2,···,X6来自总体N(0,1), =(({X)_(1)+(X)_(2)+(X)_(3))}^2+-|||-(({X)_(4)+(X