int_(-4)^4(sqrt(16-{{x)^2)}dx}(=)__________

[题目]计算定积分 (int )_(-4)^4sqrt (16-{x)^2}dx= __

(4)int_(1)^4(ln x)/(sqrt(x))dx;(4)$\int_{1}^{4}\frac{\ln x}{\sqrt{x}}dx;$

(3) int_(4)^9 sqrt(x)(1+sqrt(x))dx;(3) $\int_{4}^{9} \sqrt{x}(1+\sqrt{x})dx;$

(12) int_(1)^4(dx)/(1+sqrt(x));(12) $\int_{1}^{4}\frac{dx}{1+\sqrt{x}};$

17.计算定积分int_(0)^sqrt(2)(x^2)/(sqrt(4-x^2)) dx.17.计算定积分$\int_{0}^{\sqrt{2}}\frac{

计算下列各导数：(1) (d)/(dx)int_(0)^x^2sqrt(1+t^2)dt;(2) (d)/(dx)int_(x^2)^x^3(dt)/(sqrt

(4)int dfrac (sqrt {{x)^2-4}}(x)dx;

14.求定积分 int_(0)^4ln(2+sqrt(x))dx14.求定积分 $\int_{0}^{4}\ln(2+\sqrt{x})dx$

(6) int_((1)/(sqrt(2)))^1(sqrt(1-x^2))/(x^2)dx;(6) $\int_{\frac{1}{\sqrt{2}}}^{1

)int dfrac (dx)(sqrt {x)+sqrt [4](x)}