计算定积分：int_(0)^dfrac(pi {2)}(|sin x-cos x|{d)x}．

[题目]-|||-计算下列定积分.-|||-(int )_(0)^dfrac (pi {2)}|sin x-cos x|dx ;

[题目]计算定积分: (int )_(-dfrac {pi )(2)}^dfrac (pi {2)}((|x|+sin x))^2dx

int dfrac (sin x-cos x)(sin x+cos x)dx==

(d)/(dx)int_(sin x)^cos x cos(pi t^2) , dt = ( ). $\frac{d}{dx}\int_{\sin x}^{\c

设 M=int_(-(pi)/(2))^(pi)/(2) (sin x)/(1+x^2) cos^4 x dx，N=int_(-(pi)/(2))^(pi)/(

(15)int_(-(pi)/(2))^(pi)/(2)sqrt(cos x-cos^3)xdx;(15)$\int_{-\frac{\pi}{2}}^{\fr

int dfrac (sin x+cos x)(sqrt [3]{sin x-cos x)}dx

(11) int dfrac (sin x+cos x)(sqrt [3]{sin x-cos x)}dx

求下列不定积分 int dfrac (dx)(2sin x-cos x+5)求下列不定积分

(sin x)=dfrac (1)({cos )^2x} in (0,dfrac (pi )(2)),则(sin x)=dfrac (1)({cos )^2x}