20:
=
.
A dfrac (4)(5);B dfrac (4)(5);C dfrac (4)(5);D dfrac (4)(5).某学生依次进行三门课程的考试,第一门课程
(B) dfrac (5)(12). (C) dfrac (4)(5). (D) dfrac (5)(6).
dfrac (4)(5)
2.脱式计算。-|||-times dfrac (97)(99)-|||-dfrac (10)(21)times dfrac (7)(20)div dfrac
dfrac (1)(2)x+dfrac (1)(3)=dfrac (1)(4)x-dfrac (1)(5)
_(1)=5-5i, () _(2)=-3+4i 罒 (dfrac ({z)_(1)}({z)_(2)}) (整体取共-|||-A -dfrac (7)(5)-
int ((2x-5))^5dx=-|||-A dfrac (1)(8)((2x-5))^4+C-|||-B dfrac (1)(12)((2x-5))^4+C
dfrac (1)(2)pi .-|||-C.π-|||-D. dfrac (5)(4)pi .-|||-0
11设 9.ipg-|||-OA dfrac (5)(9)-|||-CB dfrac (1)(9)-|||-oc dfrac (4)(9)-|||-dfrac
比较大小: dfrac (15)(20)=dfrac (3)(4)