线性方程组r underline (1) 2 0 :7-|||-0 1 2 X= 1-|||-2 0 1 1 2-|||-0，则X=（ ）。

线性方程组的增广矩阵是1 0 2 1 1-|||-0 1 -2 1 -1-|||-0 -2 4 -2 2-|||-0 0 0 1 1则这个方程组解的情况是_。A

16.线性方程组 ) (x)_(1)+(x)_(3)=0 2(x)_(2)+(x)_(3)=0 2(x)_(1)+3(x)_(2)=0 .16.线性方程组用

已知线性方程组 ) a(x)_(1)+(x)_(3)=1 (x)_(1)+a(x)_(2)+(x)_(3)=0 (x)_(1)+2(x)_(2)+a(x)_(

设矩阵1 4 5 1 -1-|||-A= 2 -2 2 4 1-|||-0 1 -3 -5 -2-|||-3 3 4 0 -2，则齐次线性方程组1 4 5 1

5.线性方程组 ) (x)_(1)-(x)_(2)=(a)_(1) 2(x)_(2)-(x)_(3)=(a)_(2) (x)_(1)+(x)_(2)-(x)

[题目]设线性方程组 _(1)+(X)_(2)-(X)_(3)=-1-|||-(X)_(1)+K(X)_(2)-2(X)_(3)=0-|||-(X)_(1)+2

解线性方程组_(1)-2(x)_(2)+(x)_(3)=-2-|||-__ __-|||-(x)_(1)+(x)_(2)-3(x)_(3)=1-|||--(x)

399 齐次线性方程组 ) (x)_(1)+2(x)_(3)-(x)_(4)=0 (x)_(1)+(x)_(2)+ (x)_(4)=0.

求线性方程组_(1)+(x)_(2)+(x)_(3)+(x)_(4)=0-|||-_(2)+2(x)_(3)+2(x)_(4)=1-|||-_(1)+2(x)_

齐次线性方程组 ) (x)_(1)+(x)_(2)=0 (x)_(2)-(x)_(4)=0 .的基础解系为______.齐次线性方程组的基础解系为_____