1.已知 _(10)^theta (ZnS)=2.5times (10)^-22 ,_(i1)^theta ((H)_(2)S)=1.07times (10)^-7 , _(i)^theta ((H)_(2)S)=1.26times (10)^-13-|||-,欲使0.050mol的zns在1.0L的HO1中恰好全部溶解,则该-|||-Ha浓度 (molcdot (L)^-1) 应为:-|||-A 0.24-|||-B 0.14-|||-C 0.37

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