证明反常积分
绝对收敛.
证明反常积分
绝对收敛.
19、单选 反常积分 (int )_(0)^+infty dfrac (1)(1+x+{x)^2}dx= __-|||-(3分-|||-A) .dfrac (s
(int )_(-infty )^+infty (x)^2(e)^-a(x^2)dx=dfrac (1)(2)sqrt (dfrac {pi )({a)^3}}
1.判定下列各反常积分的收敛性,如果收敛,计算反常积分的值:-|||-(1) (int )_(1)^+infty dfrac (dx)({x)^4}-|||-(
求下列不定积分:-|||-(1) int dfrac (1)(5x-3)dx ;-|||-(3) int dfrac (1)(sqrt {x+1)+sqrt (
【例9】 (2015年考研数二)下列反常积分收敛的是 () .-|||-(A) (int )_(2)^+infty dfrac (1)(sqrt {x)}dx
int dfrac (sin x+cos x)(sqrt [3]{sin x-cos x)}dx
(1) int dfrac (3sqrt {x)}(x(sqrt {x)+sqrt [3](x))}dx
计算积分(int )_(dfrac {1)(2)}^dfrac (3{2)}dfrac (dx)(sqrt {|x-{x)^2|}}.(本题满分6分)计算积分.
1.以下各积分不属于反常积分的是 () .-|||-(A) (int )_(0)^+infty ln (1+x)dx (B) (int )_(0)^1dfrac
(11) int dfrac (sin x+cos x)(sqrt [3]{sin x-cos x)}dx