;
求 int (sin )^4xdx
(0.7分)int sin 4xdx=dfrac (1)(4)int sin 4xdx=dfrac (1)(4)cos 4x+cA 正确B 错误89
(int )_(0)^dfrac (pi {4)}(tan )^2xdx=1-dfrac (pi )(4) __-|||-__下列式子或叙述不正确的是A.B.设
设=(int )_(-dfrac {pi )(2)}^dfrac (pi {2)}dfrac (sin x)(1+{x)^2}(cos )^4xdx, =(in
15) int tan^10xcdotsec^2xdx;15) $\int \tan^{10}x\cdot\sec^{2}xdx;$
5.设 _(1)=(int )_(0)^1xdx , _(2)=(int )_(0)^1sin xdx , _(3)=(int )_(0)^1tan xdx,
(5) int (tan )^10xcdot (sec )^2xdx;
-tan xdx-|||-c.tan xdx-|||-D. -tan x +
int tan sqrt (1+{x)^2}cdot dfrac (xdx)(sqrt {1+{x)^2}}