已知_(square )=dfrac (1)(4) ,_(1)=dfrac (1)(2) ,_(2)=dfrac (3)(4) ,(1)推导以这三点为求积节点在_(square )=dfrac (1)(4) ,_(1)=dfrac (1)(2) ,_(2)=dfrac (3)(4) ,上的插值型求积公式_(square )=dfrac (1)(4) ,_(1)=dfrac (1)(2) ,_(2)=dfrac (3)(4) ,;(2)指明求积公式所具有的代数精度;(3)用所求公式计算_(square )=dfrac (1)(4) ,_(1)=dfrac (1)(2) ,_(2)=dfrac (3)(4) ,。

f(x)= ({e)^4-dfrac (1)(3))-|||-dfrac (1)(2)(e)^4-|||-dfrac (1)(2)((e)^2-dfrac

已知_(1)=((dfrac {1)(3),-dfrac (2)(3),-dfrac (2)(3))}^T, _(2)=((-dfrac {2)(3),dfra

曲线 =dfrac (1)(x) 在点 (dfrac (1)(2),2) 处的切线的斜率为 ()-|||-A dfrac (1)(4)-|||-B -4-|||

dfrac (1)(2)x+dfrac (1)(3)=dfrac (1)(4)x-dfrac (1)(5)

((y+dfrac {1)(2))}^2=dfrac (3)(4) D. ((y-dfrac {1)(2))}^2=dfrac (3)(4)

已知 (A)=dfrac (1)(2) ,(B)=dfrac (1)(3) ,-|||-(C)=dfrac (1)(5) ,(AB)=dfrac (1)(10)

已知 (A)=dfrac (1)(2) , (B)=dfrac (1)(3) , (C)=dfrac (1)(5)-|||-, (AB)=dfrac (1)(1

已知 (A)=dfrac (1)(2) ,(B)=dfrac (1)(3) ,-|||-(C)=dfrac (1)(5) ,(AB)=dfrac (1)(10)

下列选项中曲面dfrac ({x)^2}(4)+dfrac ({y)^2}(1)+dfrac ({z)^2}(9)=3上点dfrac ({x)^2}(4)+df

(D) (hat {mu )}_(4)=dfrac (1)(3)(X)_(1)+dfrac (3)(4)(X)_(2)-dfrac (1)(12)(X)_(3)