[题目]-|||-18、单选下列积分的效散性说法错误的是(), ()-|||-()-|||-A (int )_(0)^1dfrac (dx)(1-{x)^4}
(int )_(0)^1dfrac (dx)({x)^2sqrt (1-x)} 发散-|||-D (int )_(0)^1dfrac (dx)(xsqrt {1
(int )_(0)^1dfrac (x)(sqrt {1-{x)^2}}dx= [填空1]
计算定积分(int )_(0)^1dfrac (x)(x+1)sqrt (1-{x)^2}dx.计算定积分.
求下列定积分:-|||-(int )_(dfrac {sqrt {2)}(2)}^1dfrac (sqrt {1-{x)^2}}({x)^2}dx
(int )_(0)^1dfrac (x+2)(sqrt {x+1)}dx=( )(int )_(0)^1dfrac (x+2)(sqrt {x+1)}dx=
(int )_(0)^1dfrac (1)(1+5x)dx
计算下列定积分.-|||-(int )_(dfrac {sqrt {2)}(2)}^1dfrac (sqrt {1-{x)^2}}({x)^2}dx -
计算下列定积分。-|||-(int )_(0)^1dfrac ({x)^4}(1+{x)^2}dx
(4)若 (int )_(0)^1f(x)dx=agt 0, 则 (int )_(0)^1dfrac (1)(sqrt {x)}f(sqrt (x))dx=()