1.摆线 ^2dt (B){int )_(0)^2ma(x)^2((1-cos t))^2da(t-sin t)-|||-(C) [π^2π]^2(1-cost)^2dt (D) (int )_(0)^2pi (a)^2((1-cos t))^2da(t-sin t)

(2)已知函数f(x)=int_(0)^sin xsin t^2dt,g(x)=int_(0)^sin xf(t)dt,则A. f(x)是奇函数,g(x)是奇函

(2)已知函数f(x)=int_(0)^sin xsin t^2dt,g(x)=int_(0)^sin xf(t)dt,则（）A. f(x)是奇函数,g(x)是

摆线{}x=a(t-sin t)y=a(1-cos t)dtA. $\int_{0}^{2\pi a}\pi a^{2}(1-\cos t)^{2}d[a(t-

求下列极限：(1)lim _(xarrow 0)((int )_(0)^xcos (t)^2dt)/(x)；(2)underset(xto 0)(mathrm{

(1) lim _(xarrow 0)dfrac ({({int )_(0)^x(e)^(t^2)dt)}^2}({int )_(0)^xt(e)^2(t^2)

1.求极限 lim _(xarrow 0)dfrac ({int )_(0)^x(tan t-sin t)dt}(({e)^(x^2)-1)cdot ln (1

求极限lim _(xarrow 0)dfrac ({int )_(0)^xcos (t)^2dt}(ln (1+x))求极限

11.求下列极限:-|||-(1) lim _(xarrow 0)dfrac ({int )_(0)^xcos (t)^2dt}(x)

lim _(xarrow 0)dfrac ({int )_(x)^0((e)^t+(e)^-t-2)dt}(1-cos x) ()-|||-__=（）=（）A.

注 类似地，求极限lim_(xto0)[(1)/(xint_(0)^xtan t^2dt)-(1)/(xint_(0)^xsin t^2dt)].注 类似地