已知：(rm N_{2)(g)+O_(2)(g)=2NO(g)triangle H_(1)=+180.5KJboldsymbol(⋅)mol^-1}①(rm 2C(s)+O_{2)(g)=2CO(g)triangle H_(2)=-221.0KJboldsymbol(⋅)mol^-1}②(rm C(s)+O_{2)(g)=CO_(2)(g)triangle H_(3)=-393.5KJboldsymbol(⋅)mol^-1}③则能表示汽车尾气转化的热化学方程式为(rm ( )) A、(rm 2NO(g)+2CO(g)=N_{2)(g)+2CO_(2)(g)triangle H=-746.5:KJboldsymbol(⋅)mol^-1} B、(rm 2NO(g)+2CO(g)=N_{2)(g)+2CO_(2)(g)triangle H=+746.5:KJboldsymbol(⋅)mol^-1} C、(rm 2NO(g)+2CO(g)=N_{2)(g)+2CO_(2)(g)triangle H=-1:493:KJboldsymbol(⋅)mol^-1} D、(rm 2NO(g)+2CO(g)=N_{2)(g)+2CO_(2)(g)triangle H=+1:493:KJboldsymbol(⋅)mol^-1}

已知：${\rm N_{2}(g)+O_{2}(g)=2NO(g)\triangle H_{1}=+180.5KJ\boldsymbol{⋅}mol^{-1}}$①
${\rm 2C(s)+O_{2}(g)=2CO(g)\triangle H_{2}=-221.0KJ\boldsymbol{⋅}mol^{-1}}$②
${\rm C(s)+O_{2}(g)=CO_{2}(g)\triangle H_{3}=-393.5KJ\boldsymbol{⋅}mol^{-1}}$③
则能表示汽车尾气转化的热化学方程式为${\rm (\quad)}$    A、${\rm 2NO(g)+2CO(g)=N_{2}(g)+2CO_{2}(g)\triangle H=-746.5\:KJ\boldsymbol{⋅}mol^{-1}}$  B、${\rm 2NO(g)+2CO(g)=N_{2}(g)+2CO_{2}(g)\triangle H=+746.5\:KJ\boldsymbol{⋅}mol^{-1}}$  C、${\rm 2NO(g)+2CO(g)=N_{2}(g)+2CO_{2}(g)\triangle H=-1\:493\:KJ\boldsymbol{⋅}mol^{-1}}$  D、${\rm 2NO(g)+2CO(g)=N_{2}(g)+2CO_{2}(g)\triangle H=+1\:493\:KJ\boldsymbol{⋅}mol^{-1}}$

参考答案与解析：

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