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(int )_(0)^1dfrac (dx)({x)^2sqrt (1-x)} 发散-|||-D (int )_(0)^1dfrac (dx)(xsqrt {1
4.9 计算下列定积分:-|||-(6) (int )_(dfrac {3)(4)}^1dfrac (1)(sqrt {1-x)-1}dx.
不定积分int dfrac (1)(1+sqrt {1-x)}dx=( ) int dfrac (1)(1+sqrt {1-x)}dx=int dfrac (
int dfrac (1)({x)^2}sqrt (dfrac {1-x)(1+x)}dx
(4)若 (int )_(0)^1f(x)dx=agt 0, 则 (int )_(0)^1dfrac (1)(sqrt {x)}f(sqrt (x))dx=()
(int )_(0)^1dfrac (x+2)(sqrt {x+1)}dx=( )(int )_(0)^1dfrac (x+2)(sqrt {x+1)}dx=
int dfrac (1-x)(sqrt {9-4{x)^2}}dx=________=________
(int )_(0)^1dfrac (x)(sqrt {1-{x)^2}}dx= [填空1]
(26) int dfrac (1-x)(sqrt {9-4{x)^2}}dx
求下列定积分:-|||-(int )_(dfrac {sqrt {2)}(2)}^1dfrac (sqrt {1-{x)^2}}({x)^2}dx