用克莱姆法则求解线性方程组 } 2x_1+x_2-5x_3+x_4=8x_1-3x_2 -6x_4=9 2x_2-x_3+2x_4=-5x_1+4x_2-7x_3+6x_4=0,则得 x_1=______ ;x_2=______ ;x_3=______ ;x_4=______ .

用克莱姆法则求解线性方程组 $\begin{cases} 2x_1+x_2-5x_3+x_4=8\\x_1-3x_2\quad\quad
-6x_4=9\\ \quad\quad 2x_2-x_3+2x_4=-5\\x_1+4x_2-7x_3+6x_4=0\end{cases}$,则得 $x_1=$______ ;$x_2=$______ ;$x_3=$______ ;$x_4=$______ .

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