A.dfrac ({C)_(7)^1(C)_(5)^1}({C)_(12)^2}dfrac (2)(7)-|||-:dfrac (2)(12) B. dfrac ({C)_(7)^1(C)_(5)^1}({C)_(12)^2}dfrac (2)(7)-|||-:dfrac (2)(12) C.dfrac ({C)_(7)^1(C)_(5)^1}({C)_(12)^2}dfrac (2)(7)-|||-:dfrac (2)(12) D.dfrac ({C)_(7)^1(C)_(5)^1}({C)_(12)^2}dfrac (2)(7)-|||-:dfrac (2)(12)

袋中有12个球，其中7个白球，5个黑球，从中任取2个，则至少有一个黑球的概率( ).

A. B. C. D.

参考答案与解析：

相关试题

dfrac (1)(12)-|||-(B) dfrac (1)(2) .-|||-C dfrac (1)(8)-|||-) dfrac (1)(6): dfrac (1)(12)-|||-(B) dfrac (1)(2) .-|||-C dfrac (1)(8)-|||-) dfrac (1)(6)

查看答案

int ((2x-5))^5dx=-|||-A dfrac (1)(8)((2x-5))^4+C-|||-B dfrac (1)(12)((2x-5))^4+C-|||-C dfrac (1)(12): int ((2x-5))^5dx=-|||-A dfrac (1)(8)((2x-5))^4+C-|||-B dfrac (1)(12)((2x-5))^4+C

查看答案

(B) dfrac (7)(8) . (C) dfrac (5)(8) . (D) dfrac (1)(8): (B) dfrac (7)(8) . (C) dfrac (5)(8) . (D) dfrac (1)(8)

查看答案

dfrac (1)(7)-|||-C dfrac (1)(15)-|||-D dfrac (1)(3): dfrac (1)(7)-|||-C dfrac (1)(15)-|||-D dfrac (1)(3)

查看答案

dfrac (1)(5)(X)_(1)+dfrac (2)(5)(X)_(2)+dfrac (2)(5)(X)_(3)-|||-D .dfrac (1)(7)(X)_(1)+dfrac (2)(7)(: dfrac (1)(5)(X)_(1)+dfrac (2)(5)(X)_(2)+dfrac (2)(5)(X)_(3)-|||-D .dfrac (1)(7)(

查看答案

定积分 ^2-dfrac (1)(x)+C ()()-|||-A dfrac (1)(2)(x)^2+dfrac (1)(x)+C-|||-B dfrac (1)(2)(x)^2-dfrac (1)(: 定积分 ^2-dfrac (1)(x)+C ()()-|||-A dfrac (1)(2)(x)^2+dfrac (1)(x)+C-|||-B dfrac (1

查看答案

,,UNDUNDUND上的可能是-|||-()-|||-A.dfrac (1)(10)-|||-B.dfrac (1)(5)-|||-C.dfrac (1)(3)-|||-D.dfrac (1)(2): ,,UNDUNDUND上的可能是-|||-()-|||-A.dfrac (1)(10)-|||-B.dfrac (1)(5)-|||-C.dfrac (1)(3

查看答案

已知 (A)=dfrac (1)(2) ,(B)=dfrac (1)(3) ,-|||-(C)=dfrac (1)(5) ,(AB)=dfrac (1)(10) ,-|||-(AC)=dfrac (1: 已知 (A)=dfrac (1)(2) ,(B)=dfrac (1)(3) ,-|||-(C)=dfrac (1)(5) ,(AB)=dfrac (1)(10)

查看答案

已知 (A)=dfrac (1)(2) , (B)=dfrac (1)(3) , (C)=dfrac (1)(5)-|||-, (AB)=dfrac (1)(10) , (AC)=dfrac (1)(: 已知 (A)=dfrac (1)(2) , (B)=dfrac (1)(3) , (C)=dfrac (1)(5)-|||-, (AB)=dfrac (1)(1

查看答案

已知 (A)=dfrac (1)(2) ,(B)=dfrac (1)(3) ,-|||-(C)=dfrac (1)(5) ,(AB)=dfrac (1)(10) ,-|||-(AC)=dfrac (1: 已知 (A)=dfrac (1)(2) ,(B)=dfrac (1)(3) ,-|||-(C)=dfrac (1)(5) ,(AB)=dfrac (1)(10)

查看答案