(int )_(0)^5dfrac (2{x)^2+3x-5}(x+3)dx

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1.计算下列定积分:-|||-(22) (int )_(-5)^5dfrac ({x)^3(sin )^2x}({x)^4+2(x)^2+1}dx ;: 1.计算下列定积分:-|||-(22) (int )_(-5)^5dfrac ({x)^3(sin )^2x}({x)^4+2(x)^2+1}dx ;

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int dfrac (2cdot {3)^x-5cdot (2)^x}({3)^x}dx-|||-__；: int dfrac (2cdot {3)^x-5cdot (2)^x}({3)^x}dx-|||-__；；

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int dfrac (5x-1)({x)^2-x-2}dx= (.A.int dfrac (5x-1)({x)^2-x-2}dx= (B.int dfrac (5x-1)({x)^2-x-2}dx=: int dfrac (5x-1)({x)^2-x-2}dx= (.A.int dfrac (5x-1)({x)^2-x-2}dx= (B.int dfrac (

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int dfrac ({x)^3}({(1+{x)^2)}^2}dx=A.int dfrac ({x)^3}({(1+{x)^2)}^2}dx=B.int dfrac ({x)^3}({(1+{x)^: int dfrac ({x)^3}({(1+{x)^2)}^2}dx=A.int dfrac ({x)^3}({(1+{x)^2)}^2}dx=B.int df

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设=5(x)^3-(2)^x+3(e)^x+2，则=5(x)^3-(2)^x+3(e)^x+2=( ).A.=5(x)^3-(2)^x+3(e)^x+2B.=5(x)^3-(2)^x+3(e): 设=5(x)^3-(2)^x+3(e)^x+2，则=5(x)^3-(2)^x+3(e)^x+2=( ).A.=5(x)^3-(2)^x+3(e)^x+2

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计算(int )_(0)^+infty dfrac (dx)({x)^2+4x+3}的值是A (int )_(0)^+infty dfrac (dx)({x)^2+4x+3}B (int )_(0)^: 计算(int )_(0)^+infty dfrac (dx)({x)^2+4x+3}的值是A (int )_(0)^+infty dfrac (dx)({x)^

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填空:-|||-(1) int (x)^3(e)^xdx= __ ;-|||-(2) int dfrac (x+5)({x)^2-6x+13}dx= __: 填空:-|||-(1) int (x)^3(e)^xdx= __ ;-|||-(2) int dfrac (x+5)({x)^2-6x+13}dx= __

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求int dfrac (4{x)^5-3(x)^4+3x}(1+{x)^2}dx: 求int dfrac (4{x)^5-3(x)^4+3x}(1+{x)^2}dx求

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int dfrac (x)(3-2{x)^2}dx;: int dfrac (x)(3-2{x)^2}dx;

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(2) (int )_(-2)^1dfrac (dx)({(11+5x))^3} :: (2) (int )_(-2)^1dfrac (dx)({(11+5x))^3} :

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