计算(int )_(-1)^1sqrt [3]({x)^2}(sin )^5xdx

int (sin )^3x(cos )^5xdx= __ A.int (sin )^3x(cos )^5xdx= __ B.int (sin )

定积分(int )_(0)^1sqrt (2x-{x)^2}dx=( )(int )_(0)^1sqrt (2x-{x)^2}dx=( )(int )_(0

5.设 _(1)=(int )_(0)^1xdx , _(2)=(int )_(0)^1sin xdx , _(3)=(int )_(0)^1tan xdx,

int tan sqrt (1+{x)^2}cdot dfrac (xdx)(sqrt {1+{x)^2}}

(int )_(-1)^1dfrac (xdx)(sqrt {5-4x)}

(int )_(-1)^1dfrac (xdx)(sqrt {5-4x)}

1.求下列不定积分:-|||-(1) int dfrac (sqrt {x)-2sqrt [3](x)-1}(sqrt [4]{x)}dx-|||-(2)far

(19) int tan sqrt (1+{x)^2}cdot dfrac (xdx)(sqrt {1+{x)^2}}-|||-(20) int dfrac (

(19) int tan sqrt (1+{x)^2}cdot dfrac (xdx)(sqrt {1+{x)^2}}-|||-(20) int dfrac (

(11) (int )_(-1)^1dfrac (xdx)(sqrt {5-4x)};