直线dfrac (x-1)(2)=dfrac (y)(-1)=dfrac (z-2)(3)-|||-__与直线dfrac (x-1)(2)=dfrac (y)(
[题目]点(0,1)到直线 () x+y+1=0 的距离是 ()-|||-A、1-|||-B、2-|||-C、 dfrac (sqrt {2)}(2)-|||-
过直线_(1):dfrac (x-1)(1)=dfrac (y-2)(0)=dfrac (z-3)(-1)-|||-__ __且平行于直线_(1):dfrac
3、设 (x,y)=arctan dfrac (x)(y), 则 (1,1)=-|||-(A)1; (B)0; (C) dfrac {1)(2),dfrac
直线dfrac (x-1)(1)=dfrac (y)(2)=dfrac (z+3)(-2)-|||-__ __-|||-__与平面dfrac (x-1)(1)=
一直线过点 M(1,2,1),垂直于直线 _(1):dfrac (x-1)(3)=dfrac (y)(2)=dfrac (z+1)(1), 且和直线 _(2):
下列直线中,经过点 A ( -1 , 2 ) 的是 ( ).A.y=2x-1B.y=-dfrac (1)(3)x+dfrac (7)(3)C.y-3=-d
3、过直线 _(1):dfrac (x-1)(1)=dfrac (y-2)(0)=dfrac (z-3)(-1) 且平行于直-|||-线 _(2):dfrac
6.设 (x,y)=dfrac (x-{y)^2+(y)^3}(2x+{y)^2}, 则,lim h(x,y)等于 ()-|||-(A) dfrac (1)(2
2.设D |x|+|y|leqslant 1, 则 iint (|x|+y)dxdy= () .-|||-(A)0 (B) dfrac (1)(3) (C) d