已知函数f(x)在点x0处可导,则下列极 限 中 () 等于导数值f`(x0).-|||-(A) lim _(harrow 0)dfrac (f({x)_(0)+2h)-f((x)_(0))}(h) (B) lim _(harrow 0)dfrac (f({x)_(0)-3h)-f((x)_(0))}(h)-|||-(C) lim _(harrow 0)dfrac (f({x)_(0))-f((x)_(0)-h)}(h) (D) lim _(harrow 0)dfrac (f({x)_(0))-f((x)_(0)+h)}(h)

(6)设f(x)在x0处可导,则 lim _(harrow 0)dfrac (f({x)_(0)+h)-f((x)_(0)-h)}(h)= () ;-|||-(

若极限lim _(harrow 0)dfrac (f({x)_(0)+2h)-f((x)_(0))}(h)=dfrac (1)(2)，则导数值lim _(har

若函数f（x）在点x0处可导，则极限underset(lim)(h→0)(f（(x)_(0)+3h）-f（(x)_(0)-h）)/(2h)=（ ）A. 4f′（

(f(x)在 _{0)=(x)_(0) 处可导,且 lim _(harrow 0)dfrac (f({x)_(0)+2h)-f((x)_(0)-h)}(2h)=

(1)若f(x)在 =(x)_(0) 处可导,则 () .-|||-(A) lim _(harrow 0)dfrac (f({x)_(0)+2h)-f((x)_

(2)已知f(x)在 =(x)_(0) 处可导,且有 lim _(harrow 0)dfrac (2h)(f({x)_(0))-f((x)_(0)-4h)}=-

[单选题]已知函数在x0处可导，且｛x／[f（x0-2x）-f（x0）]｝=1／4，则f′（x0）的值为：（）A . 4B . -4C . -2D . 2

[单选题]若f（x）在x0点可导，则|f（x）|在点x0点处（　　）.A.必可导B.连续但不一定可到C.一定不可导D.不连续

[单选题]若f（x）在x0点可导，则|f（x）|在点x0点处（　　）.A.必可导B.连续但不一定可到C.一定不可导D.不连续

[单选题]若f（x）在x0点可导，则|f（x）|在点x0点处（　　）.A.必可导B.连续但不一定可到C.一定不可导D.不连续