
[题目] int (cos )^2dfrac (x)(2)dx= __
(int )_(0)^dfrac (pi {4)}dfrac (x)(1+cos 2x)dx=( ) .(int )_(0)^dfrac (pi {4)}dfr
9.int x(cos )^2dfrac (x)(2)dx9.
(int )_(-dfrac {pi )(2)}^dfrac (pi {2)}((cos )^2x+dfrac (xcos x)(1+{cos )^2x})dx
(int )_(-dfrac {pi )(2)}^dfrac (pi {2)}dfrac (|x|sin x)(1+{cos )^3x}dx=(int )_(-
(3) (int )_(0)^dfrac (pi {4)}dfrac (x)(1+cos 2x)dx= () .-|||-(A) dfrac (pi )(8)+
(int )_(0)^2dfrac (dx)({(1-x))^2};;
(int )_(0)^2dfrac (dx)({(1-x))^2};
[题目]求不定积分: (int )(cos )^2dfrac (x)(2)dx
求(int )_(0)^2dfrac (dx)({(1-x))^2}求