求下列极限:lim _(xarrow 0)dfrac (sin x-tan x)((sqrt [3]{1+{x)^2}-1)(sqrt (1+sin x)-1)}

求下列极限:

参考答案与解析:

相关试题

lim _(xarrow 0)dfrac (sin x-tan x)((sqrt [3]{1+{x)^2}-1)(sqrt (1+sin x)-1)}= __

lim _(xarrow 0)dfrac (sin x-tan x)((sqrt [3]{1+{x)^2}-1)(sqrt (1+sin x)-1)}= __

  • 查看答案
  • [题目] lim _(xarrow 0)dfrac (sin x-tan x)((sqrt [3]{1+{x)^2}-1)(sqrt (1+sin x)-1)}

    [题目] lim _(xarrow 0)dfrac (sin x-tan x)((sqrt [3]{1+{x)^2}-1)(sqrt (1+sin x)-1)}

  • 查看答案
  • (4) lim _(xarrow 0)dfrac (sin x-tan x)((sqrt [3]{1+{x)^2}-1)(sqrt (1+sin x)-1)}

    (4) lim _(xarrow 0)dfrac (sin x-tan x)((sqrt [3]{1+{x)^2}-1)(sqrt (1+sin x)-1)}

  • 查看答案
  • 1、计算极限 lim _(xarrow 0)dfrac (sin x-tan x)({x)^2(sqrt (1+sin x)-1)}

    1、计算极限 lim _(xarrow 0)dfrac (sin x-tan x)({x)^2(sqrt (1+sin x)-1)}

  • 查看答案
  • (10) lim _(xarrow 0)dfrac (tan x-sin x)((sqrt [3]{1+{x)^2}-1)(sqrt (1+sin x)-1)}

    (10) lim _(xarrow 0)dfrac (tan x-sin x)((sqrt [3]{1+{x)^2}-1)(sqrt (1+sin x)-1)}

  • 查看答案
  • (6) lim _(xarrow 0)dfrac (sqrt {1+tan x)-sqrt (1+sin x)}(xsqrt {1+{sin )^2x}-x}

    (6) lim _(xarrow 0)dfrac (sqrt {1+tan x)-sqrt (1+sin x)}(xsqrt {1+{sin )^2x}-x}

  • 查看答案
  • [题目] lim _(xarrow 0)dfrac (sqrt {1+tan x)-sqrt (1+sin x)}(xsqrt {1+{sin )^2x}-x}

    [题目] lim _(xarrow 0)dfrac (sqrt {1+tan x)-sqrt (1+sin x)}(xsqrt {1+{sin )^2x}-x}

  • 查看答案
  • 求极限:lim _(xarrow 0)dfrac (3x)(1-sqrt {1+sin x)}

    求极限:lim _(xarrow 0)dfrac (3x)(1-sqrt {1+sin x)}求极限:

  • 查看答案
  • lim _(xarrow 0)dfrac (sin 2x-2sin x)(x(sqrt [3]{1+{x)^2}-1)}.

    lim _(xarrow 0)dfrac (sin 2x-2sin x)(x(sqrt [3]{1+{x)^2}-1)}..

  • 查看答案
  • .求极限 lim _(xarrow 0)dfrac (x-tan x)(xln (1+{x)^2)}

    .求极限 lim _(xarrow 0)dfrac (x-tan x)(xln (1+{x)^2)}

  • 查看答案