将dfrac ({x)^2}(1-sqrt {1+{x)^2}}进行分母有理化.

) lim _(xarrow 1)dfrac ((1-sqrt {x))(1-sqrt [3](x))}({(1-x))^2}

=dfrac (arcsin x)(x)+dfrac (1)(2)ln dfrac (1-sqrt {1-{x)^2}}(1+sqrt {1-{x)^2}}

极限lim _(xarrow 0)dfrac (1-sqrt {1-{x)^2}cos x}(1+{x)^2-(cos )^2x}=极限

做有理化dfrac (sqrt {x+2)-sqrt (3)}(x-1)做有理化

int tan sqrt (1+{x)^2}cdot dfrac (xdx)(sqrt {1+{x)^2}}

极限 lim _(xarrow 0)dfrac ({(2+cos x))^x-(3)^x}((1-sqrt {1-{x)^2})ln (1+} 为() ()

(19) int tan sqrt (1+{x)^2}cdot dfrac (xdx)(sqrt {1+{x)^2}}-|||-(20) int dfrac (

(19) int tan sqrt (1+{x)^2}cdot dfrac (xdx)(sqrt {1+{x)^2}}-|||-(20) int dfrac (

lim _(xarrow 0)dfrac (sqrt {1+x)+sqrt (1-x)-2}(sqrt {1+{x)^2}-1}

(int )_(1)^sqrt (3)dfrac (dx)({x)^2sqrt (1+{x)^2}};